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...  when Come-From-Beyond and BCNext were running the show ...

this "and" sounds interesting   

Merci beaucoup, Ludom!

http://www.ledgerjournal.org/ojs/index.php/ledger/issue/view/2/showToc

http://www.ledgerjournal.org/ojs/index.php/ledger/article/download/46/60

HI, you should update the opening post to make obvious that the Jinn to Iota exchange is finished  .

Yesterday,  I did send Jinn to the NXT address and entered the iota address in http://collect.iotatoken.com/ . I had no message on the way saying that the collect is finished.

What is going to happen to my Jinn token ? Will they be changed into iota or refund to my NXT account ? ( nxt account : NXT-J6BE-JL6S-EY39-F7PMD )

Nicolas

See https://bitcointalk.org/index.php?topic=1262688.msg13605469#msg13605469

You have to contact Come-from-Beyond (on bitcointalk, not here).

Интересно, не хочет ли кто-нибудь сделать форк некста с алгоритмом Transparent Forging-а, описанным в разделе 8 в https://www.docdroid.net/ecmz/forging0-5-2.pdf.html ?   А то нанять кого-либо у меня нет денег, а последнюю мою программу я вообще написал больше двадцати лет назад. В принципе, на основе этого алгоритма можно сделать "надёжные" instant transactions, что ценно. 

Quote from: mthcl on January 12, 2016, 10:33:56 pm

OK, assume R=16, l=10, for definiteness. Imagine that there there is someone who controls, say, 10% of the stake (or, maybe, several big holders collude so that they do control 10%). Assume also that other accounts are not so big, say, each controls less than 0.1%.  Then, the 10% holder would be able to forge really a lot of blocks in a row, by dividing his stake into 100 equal parts (with overwhelming probability at least one of his accounts gets the maximal m=R).

What do you think of this attack?  In general, the situation that many small holders cannot forge anything together is worrying, I think...

I'll check both IPoS / Nxt against that, but intuitively, in this case a system is probably vulnerable. I don't worry much about such a scenario though. Economy is about Pareto distribution of wealth. Paper ( http://arxiv.org/abs/1308.3892 ) shows the Bitcoin is about stretched exponential distribution. I can't imagine a system with a single 10+% account and others hold < 0.1%.

Not necessarily single account, but maybe a collusion  of several big holders. Anyhow, that's all speculations, for now.

Could you clarify also this:

As a side note, I don't understand why you write "However, it is possible to iterate over delta" when discussing the Nxt algorithm on p.3.  Delta is in the right-hand side of (2), which is monotone, and it is not hashed. What advantage could it bring to the attacker then?

Quote from: mthcl on January 09, 2016, 08:47:58 pm

Well, even with R=8 there is a big problem with the "hidden chain" attack performed by the guy with max balance. Assume, for example, that the richest guy has 5% of the stake, and others less than 1%. Then, even if he forges alone, he'll get sometimes very heavy weights (5⁸=390625), one his block will easily overweight a very long blockchain created by all others.

Oh, that's true. I've fixed ticket's score formula with m * log2 b. Happily, simulations show the updated formula works better against attacks, so adversarial power IPoS is claimed to be safe against is raised to 1/3(33.33%). I've added you to Acknowledgement section    Uploading fixed paper to the Arxiv...

It's m times binary logarithm of b, correct?  Then there should be kind of "best splitting strategy" to maximize the forging chances (with logarithms, it's clear that getting the highest possible value of m is the best strategy). It would be interesting to do the calculations...  But it is important to observe that if everybody uses some kind of splitting strategy, then this l parameter (the number of blocks you must skip before forging the next one) is essentially unimportant (if you have a lot of small accounts, you won't "feel" this restriction).

Also, do I understand correctly that with this algorithm "small" accounts will never forge?  I mean, assume that a rich guy has balance B, and splits it into (say) 10R*l equal accounts. Then, any account that has less than B/(10R*l) has almost no chance to forge?..

Well, even with R=8 there is a big problem with the "hidden chain" attack performed by the guy with max balance. Assume, for example, that the richest guy has 5% of the stake, and others less than 1%. Then, even if he forges alone, he'll get sometimes very heavy weights (5⁸=390625), one his block will easily overweight a very long blockchain created by all others.

I'm through the paper; but let me first ask the following to remove any doubt: do you really mean that the score of a ticket is b^m (b to power m), and not simply bm? I thought it was a misprint, but it happens two times, on pp. 4 and 5...

http://pastebin.com/XrUieiJq
it's official list??

No.