The provably fair methodology works by summing up the total of the 8 leftmost digits of the txid's and modding it by the number of entrants.

You increase your chances of winning if sending in more than 1 NXT in that you receive more than 1 ticket.

1 NXT = 1 ticket

2 NXT = 2 tickets

3 NXT = 3 tickets... you get the picture.

Hi,

I'm not perfectly clear on the algorithm you are using to determine the winner, so I wonder:

If my tx id is 12345, and there are 10 entrants, my "mod result" would be 5 (12345%10=5).

Should my mod result be as low as possible in order to win?

And if I send 2 NXT instead of 1, how does that increase my chances of winning, as I only have one tx id.

Thanx

It should be clear if you look at one of the previous raffles:

https://raffle.pw/completed/83773350.htmlThe sum of all 8-digits tx ids is 36682250

**58** and the last two digits "58" name the winning ticket.

The ticket is your entry order in the raffle and you'll get one of them per NXT. Tickets are numbered from 0 to 99 in order of incoming txs per NXT, so if you i.e. spend 10 NXT and be the first one, you'll get 10 tickets from 0 to 9. If the last two digits of the tx ids sum is from "00" to "09", you'll win.

I hope, I've explained it correctly. Galimi, please correct me if I'm wrong.